1.Qd5+!!

[thematic try: 1.Qxb5+? Qf5+ 2.Qxf5+ Rxf5 3.Nxg3+ Kg6

4.Nd4 Rf7/Rf8! 5.Ngxe2 Rh7+/Rh8+ 6.Kg2 Rxh17.Kxh1

Troitzky position without the bPb5

7...b5!=;

1.Nxg3+? Kg6!=]

1...Qf5+

[1...Kg6 2.Qg5+ Kh7 3.Kg4+ Rh2 4.Rxh2+ gxh2

5.Qh4+ Kg8 6.Qd8+ Kh7 7.N4g5+ Kg6 8.Nxf7+-]

2.Qxf5+ Rxf5

3.Nxg3+ Kg6

4.Nd4! original double fork position

[4.Nxe2? Rh5+ 5.Kg2 Rxh1 6.Kxh1 b4! 7.N6d4 b3!=;

4.Nxf5? Rxe6= (4...Kxf5? 5.Nd4++-) ]

4...Rf7 5.Ngxe2

[5.Ndxe2? Rh7+ 6.Kg4 Rxh1 7.Nxh1 b4/Kf6=]

5...Rh7+

6.Kg2 Rxh1

7.Kxh1+-

and we have a Troitzky win-position thanks to the bPb5