Elmar Abdullayev (Azerbaijan)
 
#2 5+7

Try: 1. Rc5? [2. Be5#]

1. ... b4 2. R3xc4#

 But 1. ...  Bxc3 [a] !

 

Try: 1. Rf3? waiting

 1. ... Sd8/d6/a5/c5 2. Q(x)c5#

 1. ... c3 2. Qb4#

 1. ... Be1/b4/a5/e3 2. Q(x)e3 [A] #

 1. ... Bc1/c3 [a] /xf4 2. Q(x)c3 [B] #

  But 1. ... exf3!

 

Try: 1. Rg3? waiting

 1. ... Sd8/d6/a5/c5 2. Q(x)c5#

 1. ... c3 2. Qb4#

 1. ... Be1/b4/a5/e3 2. Q(x)e3 [A] #

 1. ... Bc1/c3 [a] /xf4 2. Q(x)c3 [B] #

  But 1. ... e3!

 

Try: 1. Rh3? waiting

 1. ... Sd8/d6/a5/c5 2. Q(x)c5#

 1. ... c3 2. Qb4#

 1. ... Be1/b4/a5/e3 2. Q(x)e3 [A] #

 1. ... Bc1/c3 [a] /xf4 2. Q(x)c3 [B] #

  But 1. ... c6! !

 

Solution: 

 1. Re3! [2. R3xe4#]

 1. ... Sd6/c5 2. Q(x)c5#

 1. ... c3 2. Qb4#

 1. ... Bc3 [a]  2. Qxc3 [B] #

 1. ... Bxe3 2. Qxe3 [A] #

Бристольская тема в синтезе с белой коррекцией белой ладьи