K. Velikhanov & I. Ilham Aliev (Azerbaijan)
 
#2 4+3

b) Qf8->g3
1....Ke5 2.Bc3#.
1. Bb4! [2. Qc5#]
1...Kxc4 2.Qc5#!, 1...Ke3 2.Bc5#!
1...Ke5 2.Bc3#
1...e3 2.Qf4#
 
Twin b)

1...c5 2.Qc3#!
Solution: 1. Kb3! [2. Qd6, Be3#]
1...Kc5 2.Be3#!
1...e3 2.Qxe3#!