Alberto Armeni (Italy)
 
#2 4+2

tries: 1) Rf2 zz?, Ke3/Kc3. 2) Qc5 but 1).., d2!
1) Qg5/Qh6 zz?, d2. 2) Qxd2 but 1).., Kc3!
1) Qh4+?, Ke3. 2) Qf2 changed mate but 1).., Kc3!
1) Qg4+?, Ke3. 2) Sc4 changed mate but 1).., Kc3!
1) Qf3 zz?, d2. 2) Rd5 changed mate but 1).., Kc3!
solution: 1) Q h2 thr. 2) Qe5
1).., Ke3/Kc3/d2. 2) Qf2/Qb2/Qxd2