M. Mammadov (Azerbaijan)
 
#4 4+2

2 solution

1.Bxb5? pat / stalemate.
1) 1.Kc3! Ka4 2.Sc2 b4+ 3.Kc4 b3 4.Bb5#;
2) 1.Bc8! Ka4 2.Bg4 Ka3 3.Bd1 Ka4 4.Kb2#