S. Javadzade (Azerbaijan)
 
#3 5+2

b) Ke7-d6, c=b) pb6->b7, d=c)

a) 1.Kd6 Ka8 2.Kc7 d5 3.Bb7#

b) 1.b7 Ka7 2.Kc7 d5 3.b8Q#

c) 1.Kxd7 Ka7 2.Kc8 Kb6 3.b8Q#

d) 1.Kd8 Ka7 2.Kc8 Kb6 3.b8Q#

e) 1.Kd7 Ka7 2.Kc8 Kb6 3.b8Q#

Theme: Extended problem (Author)