Richard Becker (США)
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1.b7 Rab8
[ 1...Rag8 2.Kh2 Rg8 3.Nc6 Kg5+ 4.Kg3 = ]
2.Bc6
[ 2.Bc8? a5 3.Nc6 Rbxc8 4.bxc8Q Rxc8 5.Nxa5 Rxc2 6.Kg1 Kg4 7.Kf1 Kf3 8.Ke1 Ke3 9.Kd1 Rc3 10.a4 Kd3 -+ ]
2...a5 3.Na6
[ 3.Nd3? Rh7 4.Kg2 Rc7 5.Bd5 Kg4 6.Kf1 ( 6.c4 Rcxb7 7.Bxb7 Rxb7 8.Kf2 Re7 c5 Kf5 -+ ) 6...Kf5 7.Ke2 Rxc2+ 8.Ke3 Re8+ 9.Kd4 Rd8 10.a4 Kf6 -+ ]
3...Rbg8 4.Bd5
[ 4.b8Q? Rxb8 5.Nxb8 Rxb8 6.Kg2 Rf8 -+ ] [ 4.c4? Kg4+ 5.Kg2 Kf4+ 6.Kf1 Ke3 7.Bd5 Re8 8.a4 Kd4 9.Kf2 Rhf8+ 10.Kg3 Re3+ 11.Kg4 Rb3 -+ ]
4...Rg5
[ 4...Rd8 5.Bf3+ ( also 5..c4 Kg4+ 6.Kg2 Kf4 7.Kf2 = ) 5...Kg5+ 6.Kg2 Kf4 7.Kf2 = ]
5.b8Q
[ 5.Bg2? Rb5 6.Bc6 Rb6 7.b8Q Rbxb8 8.Nxb8 Rxb8 etc. ]
5...Rxb8 6.Bf7+ Kh4 7.Nxb8 Kg3 8.Kg1 Rb5 9.Kf1 Kf3 10.Ke1
[ 10.Bb3? Rxb8 11.Ke1 Rd8 12.Bc4 Ke3 -+ ]
10...Ke3 11.Bb3 Rxb8 12.Kd1 a4 13.Ba2 Rb2 14.Kc1 Rxa2 15.Kb1 Rxa3 16.Kb2 =
Correction of 3rd Prize, Problemaz 2007
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