Alexander Shpakovsky (Россия)
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1. g3! [1. Kd2? Kc4 2. g4 Kb3 3. g5 Kxb2 4. Kxd3 a3=; 1. g4? Ke3 2. Kd1 Kf4 3. Kd2 Kxg4 4. Kxd3 a3 5. bxa3 Kf5=] 1... Ke3 [1... Kc4 2. g4+-] 2. Kd1 d2 3. g4! Kf4 4. Kxd2 Kxg4 5. Kc3 [5. Kd3? a3 6. bxa3 Kf5=; 5. Kc2? Kf5 6. Kc3 a3 7. bxa3 Ke5=] 5... a3 6. b4! [6. bxa3? Kf5 7. Kb4 (7. a4 Ke5 8. a5 Kd5 9. Kb4 Kc6=) 7... Ke6 8. Kb5 Kd7 9. Kb6 Kc8=] 6... a2 7. Kb2 a1=Q+ 8. Kxa1 Kf4 9. Kb2(a2) Ke5 10. Ka3(b3) [10. Kc3? Kd5=] 10... Kd6 11. Ka4 Kc6 12. Ka5 Kb7 13. Kb5 +- 1-0 |
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