Richard Becker (USA)
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1.Kd7! [ 1.Ke7? b4 zz 2.Kd6 ( 2.Kf6 Kc2 3.Kxg5 Kb2 = ) 2...Ke2 3.Ke6 ( 3.Ke5 Kd3 = ) 3...Kd2 zz 4.Kd5 Ke3 5.Ke5 ( 5.Kc4 Kf3 6.Kxb4 Kxg4 = ) 5...Kd3 zz 6.Kd5 Ke3 = ] 1...b4 [ 1...Ke2 2.Ke6 b4 3.Kf5 Kd2 4.Kxg5 +- ] 2.Ke7! zz [ 2.Kc6? Ke2 3.Kc5 Kf3 4.Kxb4 Kxg4 = ] 2...Kd2 [ 2...Kc2 3.Kd6 Kb2 4.Kc5 Ka3 5.Kb5 +- ] 3.Ke6 zz Kd3 4.Ke5 zz Kc4 [ 4...Kd2 5.Ke4 zz ( 5.Kd4? Ke2 6.Ke4 Kd2 = ) 5...Kc3 6.Kd5 Kd3 7.Kc5 Kc3 8.Kb5 b3 9.axb3 Kxb3 10.Kc6 +- ] 5.Ke4 zz Kb5 [ 5...Kc5 6.Kf5 Kc4 7.Kxg5 Kc3 8.Kf4 Kb2 9.g5 Kxa2 10.g6 b3 11.g7 b2 12.g8Q+ +- ] 6.Kd4 Kb6 7.Kc4 Ka5 8.Kc5 zz Ka4 9.Kb6 Ka3 10.Kb5 Kxa2 11.Kxb4 +-
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