Richard Becker (USA)
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1.Kf1! zz
[ 1.Kf2? Kh2 zz 2.Kf3 Kg1 zz ]
1...Kh2 2.Kf2 zz Kh1 3.Kg3 zz Kg1 4.Kf3 zz Kf1 5.a6! zz
[ 5.Ke3? Kg2 6.Ke2 Kg3 7.Ke3 Kg2 = ]
5...Ke1
[ 5...Kg1 6.Ke4 Kf2 7.Kd5 Ke3 8.Kc6 Kd4 9.Kb7 +- ]
6.Ke3 Kf1 7.Kd4 Ke2 8.c5 bxc5+ 9.Kxc5 Ke3 10.Kc6
Kd4 11.Kb7 Kc5 12.Kxa7 Kc6 13.Kb8 +-
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