Miroslav Sindelar (Czech Republic)
 
#3 7+7

1. Bxh3? Se2!;  1. - Qh7? 2. Bxg4!
 
1.Qh4! (tempo) Bf1 2. Se4 Kf7 3. Sd6x
1. - Se2 2. Qxh3 a 3. Bd7x
1. - d3 2. Bxh3 Sxh3 3. Qa4x
 
1. - Bxg4 2. Qxg4; 1. - Rf8 2. exf8Q+;  1. - Rg7 2. Qh8+