Alexander Shpakovsky (Россия)
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1. a5! [1. b6? Nb4 2. b7 (2. Ke5 Kg6 3. b7 Kf7 4. Kd6 Na6 5. Kxd5 Ke7=; 2. a5 Nd3+ 3. Ke3 Nc5=) 2... Na6 3. Ke5 Nc5! 4. b8=N (4. b8=Q Nd7+) 4... Nxa4=] 1... d4 [1... Nd4 2. b6 Ne6+ 3. Ke5 Nc5 4. Kxd5+-] 2. Ke4 Na3 3. b6 Nc4 4. b7 Nd6+ 5. Kf3! [5. Kxd4? Nxb7 6. a6 Nd6 7. Kc5(d5) Nc8=] 5... Nxb7 6. a6 Nd6(c5) 7. a7 +- 1-0 |
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