Alexander Shpakovsky (Россия)
 
#10 4+1

1.Kc6! Ka6 2.b4 Ka7 3.Kc7! Ka6 4.a4 Ka7  5.d4 Ka6(8) 6.d5 Ka7 7.d6 Ka6 8.d7 Ka7 9.d8=Q(R) Ka6 10.Q(R)a8#