Peter S.Krug (Аustria)  
#12 2+2


1.Kh7 h5 2.Kh6 h4 3.Kh5 h3 4.Kh4 Kh1 5.Kg3 Kg1 6.Re7 Kf1 7.Kxh3 Kf2 8.Kg4 Kg2 9.Rf7 Kh2 10.Kf3 Kh1 11.Kf2 Kh2 12.Rh7#