Peter Krug (Austria) & Mario García (Argentina)
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1...Be4+ 1...g2 2.Rb2+ e2 3.d5 g1Q 4.Bc5+ Kg3 (4...Kf3 e.g. 5.Rf8+ Kg4 6.Rb4+ Kh3 7.Rf3+ Kg2 8.Rg4+ Kxf3 9.Rxg1+-) 5.Bxg1 e1Q 6.Bf2++- 2.Kg8! Try I : 2.Kh8? g2 3.Rxe3 g1Q 4.Rxe4 Qh1+ 5.Kg8 Qxe4= 2...g2 3.Rxe3 Try II : 3.Rb2+? e2 4.Bc5 (4.Re8 Bd5+! 5.Kh7 g1Q=) 4...g1Q! (Not 4...Kf3? 5.Rf8+ Kg4 6.Rxe2 Bd5+ 7.Kxg7 g1Q 8.Re5 Bc4 9.Rff5 Qh1 10.d5+-) 5.d5+ Kf3 6.Bxg1 e1Q!= 3...Kxe3 4.d5 4.Bc5? Bd5+!= 4...Kd4 4...Bxd5+ 5.Kh8! Kd4 6.Bxg7+ Kc5 7.Rc8+ Bc6 8.Rg8 g1Q 9.Bf8++- (1) 5.Rc8 Bxd5+ 6.Kh8! Try III : 6.Kh7? Bc6! 7.Rd8+ Bd5 8.Bxg7+ Ke3 9.Rxd5 g1Q 10.Bd4+ Ke4= 6...Bc6 7.Rd8+ Bd5 7...Kc4 8.Rd1+- 8.Bxg7+ Ke3 8...Kc5 9.Rc8++- Similar at (1) 9.Re8+ Be4 9...Kd3 10.Re1+- 10.Bh6+ 10.Bf8? Kd4 11.Rd8+ Bd5= 10...Kf2 10...Kf3 11.Rg8+- 11.Bf8! 11.Rf8+? Bf3!= 11...Kf1 12.Bc5+-
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