Peter Krug (Austria)
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1.e3 Rxg3 2.Kf2 Rg4 3.g3 Ke6 4.Kg2! Try I : 4.Nc3?.Ke5 ! 5.Ne2 Kd5 6.Kg2 Kc4 7.Kh3 Kd3 8.Nc1+ Kxe3 9.Kxg4 Kf2= Try II: 4.Nd2 try 4...Kf5 5.Kg2 Rf4= 4...Kf5 4...Ke5 5.Nd2!+- 5.Nc3 Rf4 6.Ne2 Rf3 7.Nd4+ Kg4 8.Nxf3 exf3+ 9.Kf2 Kf5 10.Kxf3 g4+ 11.Kf2 Ke5 12.Ke1+-
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