Peter S.Krug (Аustria)
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1.Ra3+! Ke4 2.Nc6! 2.Ng6? Rg7 3.Rh4+ Kf5= 2...Rc7 2...Rb7 3.Ra4+ Kd5 4.Nb4+ Kc4 5.Kxe2 Kb3 6.Ra6 Nd4+ 7.Kd3 Rxb4 8.Rb1# 3.Ra4+ Kf5 3...Kd5 4.Nb4+ Kc4 5.Na6+! (5.Kxe2? Kb5=) 5...Kb5 6.Nxc7+- 3...Kf3 4.Ne5+ Kg2 5.Rh8!.N6d4 6.Rg8+- 4.Ra5+ Kf4 4...Kf6 5.Rh6+- 5.Kf2 ! 5...Rxc6 6.Rh4# mate
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