Try: 1. Bd5? ad lib 2. Bd6 (А) [3. Be5+

3. ... Rd4 4. Bxd4#] ad lib 4. Be5#

But 1. ... e3!

Try: 1. Be6? ad lib 2. Be7 (В) [3. Bf6+

3. ... Rd4 4. Bxd4#] ad lib 4. Bf6#

But 1. ... e3!

Try: 1. Bf7? ad lib 2. Bf8 (С) [3. Bg7+

3. ... Rd4 4. Bxd4#] ad lib 4. Bg7#

But 1. ... e3!

Try: 1. Bf8?(С) ad lib 2. Bg7+

2. ... Rd4 3. Bxd4#

But 1. ... Ra7!

Try: 1. Be7?(В) ad lib 2. Bf6+

2. ... Rd4 3. Bxd4#

But 1. ... Ra6!

Solution: 1. Bd6! (А)[2. Be5+

2. ... Rd4 3. Bxd4#]

1. ... Ra5 2. Bb4 [3. Bc3#]

2. ... Rb5 3. Bc3+

3. ... Rb2 4. Bxb2#

2. ... Rc5+ 3. Bxc5 ad lib 4. Bd4#

2. ... Rd5 3. Bxd5 ad lib 4. Bc3#

2. ... Ra3 3. Bxa3 ad lib 4. Bb2#

2. ... Ra2 3. Bc3+

3. ... Rb2 4. Bxb2#

Чередование вторых и первых ходов (АВС-СВА)